x^2-(2k+4)x+(k^2+3k+2)=0

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Solution for x^2-(2k+4)x+(k^2+3k+2)=0 equation: 


Simplifying
x2 + -1(2k + 4) * x + (k2 + 3k + 2) = 0

Reorder the terms:
x2 + -1(4 + 2k) * x + (k2 + 3k + 2) = 0

Reorder the terms for easier multiplication:
x2 + -1x(4 + 2k) + (k2 + 3k + 2) = 0
x2 + (4 * -1x + 2k * -1x) + (k2 + 3k + 2) = 0

Reorder the terms:
x2 + (-2kx + -4x) + (k2 + 3k + 2) = 0
x2 + (-2kx + -4x) + (k2 + 3k + 2) = 0

Reorder the terms:
x2 + -2kx + -4x + (2 + 3k + k2) = 0

Remove parenthesis around (2 + 3k + k2)
x2 + -2kx + -4x + 2 + 3k + k2 = 0

Reorder the terms:
2 + 3k + -2kx + k2 + -4x + x2 = 0

Solving
2 + 3k + -2kx + k2 + -4x + x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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